How to use
- Type into whichever of the three boxes you have, and leave the other two empty.
- Transmittance goes in as a fraction between 0 and 1; percent transmission as 0 to 100.
- The other two appear underneath. A negative absorbance is accepted — it means the sample transmits more than the blank.
💡 Exponents can be entered with e — for example, 1.5×10⁻⁵ is entered as 1.5e-5.
Formula & notes
Transmittance is the fraction of light that got through, and absorbance is minus its logarithm. That is the whole conversion; what matters is which logarithm, and the answer is the common one.
One relation, written three ways.
- Absorbance from transmittance
- A = −log₁₀(T) = 2 − log₁₀(%T)
- Transmittance from absorbance
- T = 10^(−A) %T = 100 × 10^(−A)
The scale, in whole steps
| Absorbance | Transmittance | %T | Light through |
|---|---|---|---|
| 0 | 1 | 100 | all of it |
| 0.301 | 0.5 | 50 | half |
| 1 | 0.1 | 10 | a tenth |
| 2 | 0.01 | 1 | a hundredth |
| 3 | 0.001 | 0.1 | a thousandth |
0.301 for half the light is worth memorising: it is log₁₀ 2, and it turns up whenever a dilution halves an absorbance.
Practical notes
- ⚠️ Common logarithm, base 10. JIS K 0115:2020 3.1 defines absorbance as 常用対数 outright, and IUPAC Gold Book A00028 notes that a decadic and a napierian absorbance are both in use depending on the base. A spectrophotometer reports the decadic one. Confusing them is out by ln 10 = 2.303 — large enough to matter and small enough to look like a pipetting error.
- A = 1 means one tenth of the light gets through; A = 2 means one hundredth. Each unit of absorbance is a factor of ten, which is why the useful range on a spectrophotometer is so short.
- The linear range is roughly 0.1 to 1.0 absorbance on most instruments. Above it, stray light and detector limits make the reading understate the absorbance, so the honest move is to dilute and multiply back.
- A negative absorbance means the sample transmits more than the blank. It is not impossible, it is a blanking problem — usually the wrong reference or a mark on the cuvette — so the tool converts it rather than refusing.
- Transmittance of exactly zero is refused. −log₁₀(0) is infinite rather than large, and an instrument runs out of dynamic range long before it gets there.
FAQs
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